Optimal. Leaf size=54 \[ -\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}-\frac {\text {Shi}\left (\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3} \]
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Rubi [A]
time = 0.04, antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 2, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {5778, 3379}
\begin {gather*} -\frac {\text {Shi}\left (\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3}-\frac {x^2 \sqrt {a^2 x^2+1}}{a \sinh ^{-1}(a x)} \end {gather*}
Antiderivative was successfully verified.
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Rule 3379
Rule 5778
Rubi steps
\begin {align*} \int \frac {x^2}{\sinh ^{-1}(a x)^2} \, dx &=-\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}+\frac {\text {Subst}\left (\int \left (-\frac {\sinh (x)}{4 x}+\frac {3 \sinh (3 x)}{4 x}\right ) \, dx,x,\sinh ^{-1}(a x)\right )}{a^3}\\ &=-\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}-\frac {\text {Subst}\left (\int \frac {\sinh (x)}{x} \, dx,x,\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Subst}\left (\int \frac {\sinh (3 x)}{x} \, dx,x,\sinh ^{-1}(a x)\right )}{4 a^3}\\ &=-\frac {x^2 \sqrt {1+a^2 x^2}}{a \sinh ^{-1}(a x)}-\frac {\text {Shi}\left (\sinh ^{-1}(a x)\right )}{4 a^3}+\frac {3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3}\\ \end {align*}
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Mathematica [A]
time = 0.12, size = 49, normalized size = 0.91 \begin {gather*} -\frac {\frac {4 a^2 x^2 \sqrt {1+a^2 x^2}}{\sinh ^{-1}(a x)}+\text {Shi}\left (\sinh ^{-1}(a x)\right )-3 \text {Shi}\left (3 \sinh ^{-1}(a x)\right )}{4 a^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 1.33, size = 56, normalized size = 1.04
method | result | size |
derivativedivides | \(\frac {\frac {\sqrt {a^{2} x^{2}+1}}{4 \arcsinh \left (a x \right )}-\frac {\hyperbolicSineIntegral \left (\arcsinh \left (a x \right )\right )}{4}-\frac {\cosh \left (3 \arcsinh \left (a x \right )\right )}{4 \arcsinh \left (a x \right )}+\frac {3 \hyperbolicSineIntegral \left (3 \arcsinh \left (a x \right )\right )}{4}}{a^{3}}\) | \(56\) |
default | \(\frac {\frac {\sqrt {a^{2} x^{2}+1}}{4 \arcsinh \left (a x \right )}-\frac {\hyperbolicSineIntegral \left (\arcsinh \left (a x \right )\right )}{4}-\frac {\cosh \left (3 \arcsinh \left (a x \right )\right )}{4 \arcsinh \left (a x \right )}+\frac {3 \hyperbolicSineIntegral \left (3 \arcsinh \left (a x \right )\right )}{4}}{a^{3}}\) | \(56\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{2}}{\operatorname {asinh}^{2}{\left (a x \right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {x^2}{{\mathrm {asinh}\left (a\,x\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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